b^2-7=-6b

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Solution for b^2-7=-6b equation:


Simplifying
b2 + -7 = -6b

Reorder the terms:
-7 + b2 = -6b

Solving
-7 + b2 = -6b

Solving for variable 'b'.

Reorder the terms:
-7 + 6b + b2 = -6b + 6b

Combine like terms: -6b + 6b = 0
-7 + 6b + b2 = 0

Factor a trinomial.
(-7 + -1b)(1 + -1b) = 0

Subproblem 1

Set the factor '(-7 + -1b)' equal to zero and attempt to solve: Simplifying -7 + -1b = 0 Solving -7 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '7' to each side of the equation. -7 + 7 + -1b = 0 + 7 Combine like terms: -7 + 7 = 0 0 + -1b = 0 + 7 -1b = 0 + 7 Combine like terms: 0 + 7 = 7 -1b = 7 Divide each side by '-1'. b = -7 Simplifying b = -7

Subproblem 2

Set the factor '(1 + -1b)' equal to zero and attempt to solve: Simplifying 1 + -1b = 0 Solving 1 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1b = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1b = 0 + -1 -1b = 0 + -1 Combine like terms: 0 + -1 = -1 -1b = -1 Divide each side by '-1'. b = 1 Simplifying b = 1

Solution

b = {-7, 1}

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